Top 9 đề thi giữa kì 2 Toán 6 Chân trời sáng tạo năm 2025

Vndoc Top 9 đề thi giữa kì 2 Toán 6 Chân trời sáng tạo năm 2025 5,0
\frac{{ - 1515}}{{2828}} = \frac{{ - 151515}}{{282828}}\frac{{ - 21}}{{28}} = \frac{{ - 39}}{{52}}\frac{{52}}{{91}} = \frac{{28}}{{49}}\frac{{165}}{{143}} = \frac{{26}}{{30}}\frac{{ - 32}}{{60}}\frac{{ - 16}}{{30}}\frac{{16}}{{30}}\frac{8}{{15}}\frac{{ - 8}}{{15}}\frac{7}{{ - 12}};\frac{7}{{ - 10}};\frac{{ - 7}}{8};\frac{7}{{12}}\frac{7}{{ - 12}}\frac{7}{{ - 10}}\frac{{ - 7}}{8}\frac{7}{{12}}\frac{3}{{10}}\frac{7}{2};\frac{5}{6};\frac{4}{9}\frac{{14}}{{18}};\frac{{10}}{{18}};\frac{8}{{18}}\frac{{21}}{{18}};\frac{{15}}{{18}};\frac{{12}}{{18}}\frac{{63}}{{18}};\frac{{15}}{{18}};\frac{8}{{18}}\frac{{63}}{{18}};\frac{{45}}{{18}};\frac{{63}}{{18}}\frac{0}{9};\frac{{12}}{{15}};\frac{{11}}{5};\frac{{ - 4}}{{ - 5}}\frac{0}{9}\frac{{12}}{{15}}\frac{{11}}{5}\frac{{ - 4}}{{ - 5}}2\frac{{17}}{{20}} - 1\frac{{11}}{{15}} + 6\frac{1}{{20}}:3\left( {31\frac{6}{{13}} + 5\frac{9}{{41}}} \right) - 36\frac{6}{{13}}\frac{{ - 5}}{{46}} + \frac{{ - 7}}{{25}} + \frac{{35}}{{19}} + \frac{5}{{46}} + \frac{{ - 16}}{{19}} + \frac{7}{{25}}\frac{1}{{5.6}} + \frac{1}{{6.7}} + ... + \frac{1}{{24.25}}2\frac{3}{4}x = 1\frac{{x + 2}}{8} = \frac{{ - 15}}{4}\frac{1}{27}-\frac{1}{9}\frac{1}{27}-\frac{1}{9}=\frac{0}{18}\frac{1}{27}-\frac{3}{27}=\frac{-2}{0}\frac{1}{27}-\frac{3}{27}=\frac{2}{27}\frac{1}{27}-\frac{3}{27}=\frac{1-3}{27}=\frac{-2}{27}\frac{-1}{4} \cdot \frac{1}{2}\frac{-1}{4} \cdot \frac{1}{2}=\frac{-1.2}{4.4}=\frac{-2}{4}\frac{-1}{4} \cdot \frac{1}{2}=\frac{-1}{4} \cdot \frac{2}{4}=\frac{-2}{16}\frac{-1}{4} \cdot \frac{1}{2}=\frac{-0}{8}\frac{-1}{4} \cdot \frac{1}{2}=\frac{-1}{8}\frac{4}{16}\frac{2}{8}\frac{4}{8}\frac{1}{4}\frac{1}{8}\frac{-7}{8}\frac{8}{7}\frac{7}{8}\frac{7}{-8}\frac{-8}{7}-\frac{5}{8} \cdot \frac{(-4)^{2}}{10}\frac{-2020}{2021} \cdot \frac{9}{11}+\frac{-2020}{2021} \cdot \frac{2}{11}\frac{-5}{7} \cdot \frac{2}{11}+\frac{-5}{7} \cdot \frac{9}{11}+\frac{5}{7}\frac{-3}{8} \cdot \frac{1}{2}+\frac{1}{6} \cdot \frac{-3}{8}+\frac{1}{3}: \frac{-8}{3}a) x-\frac{-1}{5}=3+\frac{-3}{2}b) \frac{1}{2}-\left(x-\frac{5}{11}\right)=\frac{-3}{4}c) \frac{3}{4}+\left(\frac{2}{5}-x\right)=\frac{1}{4}\frac{1}{3}A=\frac{9}{1.2}+\frac{9}{2.3}+\frac{9}{3.4}+\ldots+\frac{9}{98.99}+\frac{9}{99.100}Đề thi giữa kì 2 Toán 6 CTSTĐề thi giữa kì 2 Toán 6 CTST
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